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CNSP Reliable Exam Vce & Vce CNSP Format
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The SecOps Group Certified Network Security Practitioner Sample Questions (Q61-Q66):
NEW QUESTION # 61
On a Microsoft Windows operating system, what does the following command do?
net localgroup Sales Sales_domain /add
- A. Add a domain group to the local group Sales
- B. Add a new user to the local group Sales
- C. Display the list of the users of a local group Sales
- D. Add a local group Sales to the domain group
Answer: A
Explanation:
The net localgroup command manages local group memberships on Windows systems, with syntax dictating its action.
Why B is correct: net localgroup Sales Sales_domain /add adds the domain group Sales_domain to the local group Sales, granting its members local group privileges. CNSP covers this for privilege escalation testing.
Why other options are incorrect:
A: Displaying users requires net localgroup Sales without /add.
C: Adding a user requires a username, not a group name like Sales_domain.
D: The reverse (local to domain) uses net group, not net localgroup.
NEW QUESTION # 62
How would you establish a null session to a Windows host from a Windows command prompt?
- A. net use hostnamec$ "" /u:""
- B. net use hostnameipc$ "" /u:NULL
- C. net use hostnameipc$ "" /u:""
- D. net use hostnamec$ "" /u:NULL
Answer: C
Explanation:
A null session in Windows is an unauthenticated connection to certain administrative shares, historically used for system enumeration. The net use command connects to a share, and the IPC$ (Inter-Process Communication) share is the standard target for null sessions, allowing access without credentials when configured to permit it.
Why C is correct: The command net use hostnameipc$ "" /u:"" specifies the IPC$ share and uses empty strings for the password (first "") and username (/u:""), establishing a null session. This syntax is correct for older Windows systems (e.g., XP or 2003) where null sessions were more permissive, a topic covered in CNSP for legacy system vulnerabilities.
Why other options are incorrect:
A: Targets the c$ share (not typically used for null sessions) and uses /u:NULL, which is invalid syntax; the username must be an empty string ("").
B: Targets c$ instead of ipc$, making it incorrect for null session establishment.
D: Uses ipc$ correctly but specifies /u:NULL, which is not the proper way to denote an empty username.
NEW QUESTION # 63
Which of the following represents a valid Windows Registry key?
- A. HKEY_INTERNAL_CONFIG
- B. HKEY_LOCAL_USER
- C. HKEY_LOCAL_MACHINE
- D. HKEY_ROOT_CLASSES
Answer: C
Explanation:
The Windows Registry is a hierarchical database storing system and application settings, organized into predefined root keys (hives). Only specific names are valid as top-level keys.
Why A is correct: HKEY_LOCAL_MACHINE (HKLM) is a standard root key containing hardware and system-wide configuration data. CNSP references it for security settings analysis (e.g., auditing policies).
Why other options are incorrect:
B: HKEY_INTERNAL_CONFIG is not a valid key; no such hive exists.
C: HKEY_ROOT_CLASSES is a misspelling; the correct key is HKEY_CLASSES_ROOT (HKCR).
D: HKEY_LOCAL_USER is incorrect; the valid key is HKEY_CURRENT_USER (HKCU).
NEW QUESTION # 64
Which SMB (Server Message Block) network protocol version introduced support for encrypting SMB traffic?
- A. None of the above
- B. SMBv1
- C. SMBv2
- D. SMBv3
Answer: D
Explanation:
The SMB protocol, used for file and printer sharing, has evolved across versions, with significant security enhancements in later iterations.
Why C is correct: SMBv3, introduced with Windows 8 and Server 2012, added native support for encrypting SMB traffic. This feature uses AES-CCM encryption to protect data in transit, addressing vulnerabilities in earlier versions. CNSP notes SMBv3's encryption as a critical security improvement.
Why other options are incorrect:
A . SMBv1: Lacks encryption support and is considered insecure, often disabled due to vulnerabilities like WannaCry exploitation.
B . SMBv2: Introduces performance improvements but does not support encryption natively.
D . None of the above: Incorrect, as SMBv3 is the version that introduced encryption.
NEW QUESTION # 65
What will be the subnet mask for 192.168.0.1/18?
- A. 255.255.255.0
- B. 255.255.192.0
- C. 255.225.192.0
- D. 255.225.225.0
Answer: B
Explanation:
An IP address with a /18 prefix (CIDR notation) indicates 18 network bits in the subnet mask, leaving 14 host bits (32 total bits - 18). For IPv4 (e.g., 192.168.0.1):
Binary Mask: First 18 bits are 1s, rest 0s.
1st octet: 11111111 (255)
2nd octet: 11111111 (255)
3rd octet: 11000000 (192)
4th octet: 00000000 (0)
Decimal: 255.255.192.0
Calculation:
Bits: /18 = 2